# Probability Flashcards

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49/198

1/26

156/2652 = 3/51

{6, 12}

{2, 3, 4, 6, 8, 9, 10, 12}

120

1/5

2/3

1/10

30240

336

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## Flashcard Content Overview

This cards will give you practice problems on the principles of probability. In these flashcards, you'll encounter permutations and combinations, independent and dependent events, and review some basic ideas of set theory.

336

30240

1/10

2/3

1/5

120

{2, 3, 4, 6, 8, 9, 10, 12}

{6, 12}

156/2652 = 3/51

1/26

49/198

1/6

1/2

2/13

1/12

3/32

91/216

39/50

1/8000

*n*objects where

*r*are selected.

Permutation formula:

Multiply the probabilities together

*P*(

*A*U

*B*) if

*A*and

*B*are mutually exclusive?

*P*(*A* U *B*) = *P(*A*) + *P*(*B*)*

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Back To Course

Statistics 101: Principles of Statistics11 chapters | 142 lessons | 9 flashcard sets

- Go to Probability

- Go to Sampling

- Overview of Statistics Flashcards
- Summarizing Data Flashcards
- Tables and Plots Flashcards
- Probability Flashcards
- Continuous Probability Distributions Flashcards
- Regression & Correlation Flashcards
- Statistical Estimation Flashcards
- Hypothesis Testing in Statistics Flashcards
- Z-Scores & Standard Normal Curve Areas Statistical Table
- Critical Values of the t-Distribution Statistical Table
- Binomial Probabilities Statistical Tables
- Go to Studying for Statistics 101