2C8H18 + 25O2 -- 16CO2 + 18H2O The combustion of octane, C8H18, proceeds according to the...


2C{eq}_8 {/eq}H{eq}_{18} {/eq} + 25O{eq}_2 {/eq} {eq}\rightarrow {/eq} 16CO{eq}_2 {/eq} + 18H{eq}_2 {/eq}O

The combustion of octane, C{eq}_8 {/eq}H{eq}_{18} {/eq}, proceeds according to the reaction above. If 346 mol of octane combusts, what volume of carbon dioxide is produced at 37.0 degrees Celsius and 0.995 atm?

Ideal gas equation and stoichiometry

Combustion is a reaction that occurs when a hydrocarbon reacts with oxygen. Here, we have the hydrocarbon octane, combusting. The balanced reaction, which is given, shows that 2 moles of octane react to form 16 moles of carbon dioxide. The stoichiometry of the reaction will allow us to calculate the moles of carbon dioxide expected when 346mol of octane combusts. We can then use the ideal gas equation to solve for the volume of carbon dioxide:

{eq}V = \frac{nRT}{P} {/eq}

where V is volume, P is pressure, n is moles, T is temperature and R is the gas constant 0.082 {eq}\frac{Latm}{Kmol} {/eq}.

Answer and Explanation: 1

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The moles of carbon dioxide produced by the combustion of 346mol of octane can be calculated using the stoichiometry of the reaction:


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Ideal Gas Law Problems & Solutions


Chapter 4 / Lesson 5

Explore the ideal gas law equation and which law relates to the ideal gas law. See examples of ideal gas law problems and understand how to solve them.

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