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A 0.11-m long and 0.11-m wide loop is moved at a constant velocity of 0.65 m/s into a...

Question:

A 0.11-m long and 0.11-m wide loop is moved at a constant velocity of 0.65 m/s into a perpendicular constant magnetic field of 0.41 T. Calculate the magnitude of the induced voltage in the loop.

Induced Voltage:

When a conducting rod moves perpendicular to the magnetic field, an emf is induced across the ends of the conductor. This induced emf varies with the length of the conductor, velocity of the conductor and the strength of magnetic field. The rod moving in the magnetic field it cuts flux linked with it. According to Faraday law the induced emf varies with the time rate of change of flux.

Answer and Explanation:

The voltage induced in a loop of wire is:

Given:

Speed of loop, {eq}v=0.65\ m/s \\ {/eq}

Magnetic field, {eq}B=0.41\ T {/eq}

Length of loop, {eq}l=0.11\ m {/eq}

{eq}e =Blv \\ e=0.41 \times 0.11 \times 0.65 \\ e= 0.029315\ V {/eq}


Learn more about this topic:

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Faraday's Law of Electromagnetic Induction: Equation and Application

from High School Physics: Help and Review

Chapter 13 / Lesson 10
60K

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