A 0.200kg ball moves with a velocity of 0.3m/s. It collides with a second ball that is at rest...

Question:

A 0.200kg ball moves with a velocity of 0.3m/s. It collides with a second ball that is at rest and has a mass of 0.1kg. After the collision, the velocity of 0.1kg ball is 0.26m/s. What is the new velocity of the first ball.

Collision:

When the objects collide with the other object then the external force on the system remains zero, therefore the momentum of the system remains conserved.

Answer and Explanation: 1

Given

Mass of the ball 1 {eq}(m_{1}) = 0.2 \ kg {/eq}

Velocity of the ball 1 {eq}(u_{1}) = 0.3 \ m/s {/eq}

Mass of the ball 2 {eq}(m_2) = 0.1 \ kg {/eq}

Velocity of the ball 2 {eq}(u_2) = 0 m/s {/eq}

Final velocity of the ball 2 {eq}(v_2) = 0.26 \ m/s {/eq}

Now, applying the conservation of the momentum

{eq}m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2} \\ 0.2*0.3+ 0 = (0.2)v_{1} + (0.1*0.26) \\ v_{1} = 0.17 \ m/s {/eq}


Learn more about this topic:

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Linear Momentum: Definition, Equation, and Examples

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Chapter 9 / Lesson 1
204K

Any moving object has momentum, but how much momentum it has depends on its mass and velocity. In this lesson, you'll identify linear momentum, as well as see examples of how an object's momentum is affected by mass and velocity.


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