A 0.490\ \mathrm{kg} mass suspended from a spring oscillates with a period of 1.50\ \mathrm{s}....

Question:

A {eq}0.490\ \mathrm{kg} {/eq} mass suspended from a spring oscillates with a period of {eq}1.50\ \mathrm{s} {/eq}. How much mass must be added to the object to change the period to {eq}1.90\ \mathrm{s} {/eq}?

Mass added to spring

The mass oscillates to and fro on the spring when subjected to a slight disturbance. The restoring force which produces the oscillation is calculated using Hooke's Law and is proportional to the initial displacement.

Answer and Explanation:

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The time period of a mass suspended from a spring is given by:

{eq}\rm T = 2\pi \sqrt{\dfrac{m}{k}} {/eq}

Keeping all other factors constant, we...

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Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.


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