# A 1.65 kg mass stretches a vertical spring 0.290 m. If the spring is stretched an additional...

## Question:

A 1.65 kg mass stretches a vertical spring 0.290 m. If the spring is stretched an additional 0.130 m and released, how long does it take to reach the (new) equilibrium position again?

## Spring Constant:

The term spring constant in physics can be defined as the ratio of the force exerted on the spring to the per-unit compression or expansion. The measurable unit for the spring constant is in Newton per meter.

## Answer and Explanation: 1

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Given data:

• The mass is {eq}m = 1.65\,{\rm{kg}} {/eq}
• The spring stretches is {eq}x = 0.290\,{\rm{m}} {/eq}

The expression for the spring...

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#### Learn more about this topic: Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.