A 10 cm long spring is attached to the ceiling. When a 2.6 kg mass is hung from it, the spring...

Question:

A 10 cm long spring is attached to the ceiling. When a 2.6 kg mass is hung from it, the spring stretched to a length of 15 cm. What is the spring constant {eq}k {/eq} and how long is the spring when a 4.0 kg mass is suspended from it?

Hook's Law

A spring can be stretched by a applying a force F on it. Every spring has characteristic constant known as spring constant or force constant k. On application of the force the spring will be stretched until the restoring force exerted by the spring becomes equal to the applied force. Then at the state of equilibrium the applied force {eq}F = k x {/eq}. Here {eq}k x {/eq}, the product of force constant and elongation in the spring is the restoring force. This statement is known as Hook's law. If the applied force is beyond the elastic limit of the spring the law is not valid.

Answer and Explanation: 1

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Given points

  • Original length of the spring {eq}L = 0.10 \ m {/eq}
  • First mass attached to the spring {eq}m_1 = 2.6 \ kg {/eq}
  • Length of the...

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Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.


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