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A 100 g block attached to a spring with spring constant 2.9 N/m oscillates horizontally on a...

Question:

A 100 g block attached to a spring with spring constant 2.9 N/m oscillates horizontally on a frictionless table. Its velocity is 17 cm/s when {eq}x_0 = - 5.5 \ \rm cm {/eq}.

(a) What is the amplitude of the oscillation?

(b) What is the block's maximum acceleration?

(c) What is the block's position when the acceleration is maximum?

(d) What is the speed of the block when {eq}x_1 = 2.6 \ \rm cm {/eq}?

Spring Potential Energy:

Consider an object attached to a stretched spring. When the object is released, it will oscillate back and forth as the spring stretches and compresses. This motion requires kinetic energy. Where did this energy come from? It must have been stored in the original configuration of the system as potential energy.

The formula for spring potential energy is:

{eq}U = \frac{1}{2}kx^2 {/eq}

Here {eq}k {/eq} is the spring constant and {eq}x {/eq} is the spring's current displacement from its equilibrium (unstretched) position.

Answer and Explanation: 1

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The answers are (a) 6.34 cm, (b) 1.84 m/s{eq}^2 {/eq}, (c) 6.34 cm, and (d) 31.1 cm/s.

(a) At any time, this block has some kinetic energy and some...

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Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.


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