# A 12, kg block is released from rest on a 30-degree frictionless incline. Below the block is a...

## Question:

A {eq}12\, kg {/eq} block is released from rest on a 30-degree frictionless incline. Below the block is a spring that can be compressed {eq}2\, cm {/eq} by a force of {eq}270\, N {/eq}. The block momentarily stops when it compresses the spring by {eq}5.5\, cm {/eq}.

a) How far does the block move down the incline from its rest position to this stopping point?

b) What is the speed of the block just as it touches the spring?

## Spring:

Spring is used as an energy-storing device, and this specific property of spring depends upon the number of turns of the spring. The force required for the compression of the spring depends upon the spring constant.

## Answer and Explanation:

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Given data

• The mass of the block is: {eq}m = 12\;{\rm{kg}} {/eq}
• The inclination angle is: {eq}\theta = 30^\circ {/eq}
• The compression length...

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#### Learn more about this topic: Practice Applying Spring Constant Formulas

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Chapter 17 / Lesson 11
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In this lesson, you'll have the chance to practice using the spring constant formula. The lesson includes four problems of medium difficulty involving a variety of real-life applications.