Copyright

A 2.00 kg box sits on a frictionless horizontal surface. It is attached to a spring, of spring...

Question:

A 2.00 kg box sits on a frictionless horizontal surface. It is attached to a spring, of spring constant 800 N/m, so that it can oscillate horizontally.

(a) If the box is released from a point 25.0 cm from the equilibrium point, what will be the period of oscillation for the box?

(b) What is the total mechanical energy of the box?

(c) What is the speed of the box when it reaches a point 10.0 cm from equilibrium?

(d) What is the maximum speed of the box?

Simple Harmonic Motion:

Simple harmonic motion is an oscillatory motion where the net acceleration acting on the body is directed towards the equilibrium position.

Let a spring of constant k is acted upon by a force such that it got compressed by a distance x . Then the potential energy stored by the spring is given by {eq}E_P= \frac{1}{2}kx^2 {/eq} and the restoring force generated by the spring is given as {eq}F=kx {/eq}

Answer and Explanation:

Become a Study.com member to unlock this answer! Create your account

View this answer

Given:

The mass of the box is m = 2.00 kg.

The spring constant is k = 800 N/m.

The extension of the spring from which the box is released is x =...

See full answer below.


Learn more about this topic:

Loading...
Practice Applying Spring Constant Formulas

from

Chapter 17 / Lesson 11
3.4K

In this lesson, you'll have the chance to practice using the spring constant formula. The lesson includes four problems of medium difficulty involving a variety of real-life applications.


Related to this Question

Explore our homework questions and answers library