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A 2.5kg solid homogenous ball is rolling without slipping at 3 m per second to the right on a...

Question:

A 2.5kg solid homogenous ball is rolling without slipping at 3 m per second to the right on a level surface. The diameter of the ball is 80 cm. What is the total kinetic energy of the ball?.

Total Kinetic Energy:

The total kinetic energy of a rolling body is given by the equation;

{eq}K = \dfrac{1}{2} M V_{cm}^2+ \dfrac{1}{2} I \omega^2 {/eq}

where, {eq}V_{cm} {/eq} is the velocity of the center of mass of the body, {eq}\omega {/eq} is the angular velocity about the axis of rotation and I is the moment of inertia about the same axis of rotation.

Answer and Explanation:

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Given

  • The mass of solid homogeneous ball is {eq}m = 2.5\ kg {/eq}
  • Radius of the solid homogeneous ball is {eq}r = 0.8\ m {/eq}
  • The velocity of...

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Kinetic Energy of Rotation

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Chapter 7 / Lesson 7
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