# A 22.5 g sample of (NH_4)_2CO_3 (ammonium carbonate) contains _____ moles of ammonium ions. A....

## Question:

A {eq}22.5\ g {/eq} sample of {eq}\rm (NH_4)_2CO_3 {/eq} (ammonium carbonate) contains {eq}\_\_\_\_\_\ {/eq} moles of ammonium ions.

A. 0.468.

b. 0.288.

C. 0.234.

d. 2.14.

e. 3.47.

## Grams to moles of ionic compounds

The molar mass of a substance can be used to convert from grams of that substance to moles of that substance or from moles to grams. Ionic compounds consist of cations and anions in numbers that balance out their respective charges to form a neutral compound.

The chemical formula for ammonium carbonate tells us that there are 2 moles of ammonium cations in one mole of ammonium carbonate.

The number of moles of ammonium carbonate can be determined using the molar mass of ammonium carbonate, 96.1 g/mol. The moles of ammonium cation in the sample can then be determine by remembering that each mole of ammonium carbonate contains 2 moles of ammonium cations:

{eq}22.5g \cdot \frac{1mol\:(NH_4)_2CO_3}{96.1g\:(NH_4)_2CO_3} \cdot \frac{2mol\:NH_4^+}{1mol\:(NH_4)_2CO_3} =0.468mol\:NH_4^+ {/eq} 