# A 29.0 cm long spring is hung vertically from a ceiling and stretches to 37.5 cm when an 8.50 kg...

## Question:

A 29.0 cm long spring is hung vertically from a ceiling and stretches to 37.5 cm when an 8.50 kg mass is hung from its free end. Use Hooke's law and Newton's second law for the mass hanging in equilibrium. Find the spring constant (in N/m).

## Force:

The term force that can be defined as the to accelerate the object mass from its initial to the final position. Its measurable unit is Newton. The force can be stated or called as a vector quantity.

## Answer and Explanation:

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View this answer**Given data**:

- The length of the spring is {eq}l = 29.0\,{\rm{cm}} {/eq}

- The stretched length is {eq}l' = 37.5\,{\rm{cm}} {/eq}

- The mass is {eq}m =...

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Chapter 4 / Lesson 19After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.