# A 3.65\ \mathrm{kg} mass is hung from a spring with a k constant of 535.0\ \mathrm{N/m}. How far...

## Question:

A {eq}3.65\ \mathrm{kg} {/eq} mass is hung from a spring with a {eq}k {/eq} constant of {eq}535.0\ \mathrm{N/m} {/eq}. How far does the spring stretch?

## Hooke's Law

Hooke's Law if one of the fundamental principles in physics used to investigate objects undergoing simple harmonic motion. It is typically used to solve problems involving springs. It is mathematically described using the equation

$$\begin{align} F=-kx \end{align} $$

where {eq}\begin{align} F \end{align} {/eq} is the force applied on the spring, {eq}\begin{align} k \end{align} {/eq} is the spring constant, and {eq}\begin{align} x \end{align} {/eq} is the displacement of the spring.

## Answer and Explanation:

Become a Study.com member to unlock this answer! Create your account

View this answerWe are given

- {eq}\begin{align} m=3.65\, \mathrm{kg} \end{align} {/eq} = mass of the object which is hung from the spring, and

- {eq}\begin{align} k...

See full answer below.

#### Ask a question

Our experts can answer your tough homework and study questions.

Ask a question Ask a question#### Search Answers

#### Learn more about this topic:

from

Chapter 4 / Lesson 19After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.