# A 47m length of wire is stretched horizontally between two vertical posts. The wire carries a...

## Question:

A 47m length of wire is stretched horizontally between two vertical posts. The wire carries a current of 83A and experiences a magnetic force of 0.10N. Find the magnitude of the earth's magnetic field at the location of the wire, assuming the field makes an angle of 61.0 degrees with respect to the wire.

## Magnetic Force in a Current Carrying Conductor:

When an external magnetic field acts on a current carrying conductor, then it experiences a force.

This force is represented by the vector

{eq}\vec F=L.\vec i \times \vec B {/eq}

The direction of the force is given by the cross product of the direction of current and the external magnetic field.

L is the length of the conductor.

Given:

Length of the wire is L = 47 m

Current in the wire is i = 83 A.

Magnetic force is F = 0.1 N.

The angle between the magnetic field and the...

Become a Study.com member to unlock this answer! Create your account