# A 5.0-kg rock and a 3.8 x 10-4-kg pebble are held near the surface of the earth. Determine the...

## Question:

A 5.0-kg rock and a {eq}3.8 \times 10^{-4} {/eq}-kg pebble are held near the surface of the earth. Determine the magnitude of the gravitational force exerted on each by the earth.

## Gravitational Force, Acceleration Due to Gravity:

There exists a force between any two objects with mass. This force is known as 'gravitational force'. It is the force responsible for bringing every object back to ground when they are thrown upwards. It depends on the masses of the two objects and the distance between their centers of mass.

Also, because of the gravitational attraction, every object experiences a downward acceleration when placed on Earth. This downwards acceleration is called 'the acceleration due to gravity' and is constant for all the objects on the surface of the Earth, irrespective of the masses of the objects.

## Answer and Explanation:

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Given:

• The mass of the rock is {eq}m_1=5 \;\rm kg {/eq}
• The mass of the pebble is: {eq}m_2=3.8\times 10^{-4}\;\rm kg {/eq}

Near the surface of...

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#### Learn more about this topic: Gravitational Pull of the Earth: Definition & Overview

from

Chapter 15 / Lesson 17
29K

Earth's gravitational pull is often misunderstood, but without it, life on Earth would be impossible. In this lesson, we'll define the gravitational pull and give some examples of how it is used. A quiz is provided to test your understanding.