# A 50.0-kg girl bounces up and down on a pogo stick. The girl has an instantaneous acceleration of...

## Question:

A 50.0-kg girl bounces up and down on a pogo stick. The girl has an instantaneous acceleration of 2.0 m/s{eq}^2 {/eq} when the displacement is -8.0 cm. What is the spring constant of the pogo stick's spring?

## Hooke's Law:

A spring when compressed or stretched, tends to regain its original shape by exerting a force against the direction of the external force compression/extending the spring. This force is called the restoring force of the spring.

Hooke's Law is a law that quantitatively describes the restoring force of a spring. According to the law, the magnitude of the restoring force generated by a spring is proportional to the change in the length of the spring from its original length.

## Answer and Explanation:

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We are given:

• The mass of the girl, {eq}m=.050\;\rm kg {/eq}
• Her acceleration, {eq}a=2.0\;\rm m/s^2 {/eq}
• Her displacement, {eq}x=-8.0\;\rm...

See full answer below.

Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.