# A 50-kg diver leaps off the 20-meter diving board with a velocity of 5 m/s. What is his kinetic...

## Question:

A 50-kg diver leaps off the 20-meter diving board with a velocity of 5 m/s. What is his kinetic energy just before hitting the water?

## Potential and Kinetic energy:

Potential energy defined as the energy due to the virtue of the height and the kinetic energy is the energy due to the virtue of the motion. The total energy of the system always remain constant according to energy conservation.

Given

Mass of the diver (m) = 50 kg

Height of the board (h) = 20 m

Speed of the diver (u) = 5 m/s

Now, the initial energy of the diver would be

{eq}E = mgh + 0.5mv^{2} \\ E = (50*9.81*20) + (0.5*50*5^{2}) \\ E = 10435\ J {/eq}

Now, the energy at the water level become the kinetic energy, therefore the energy before hititng the water

{eq}K_{2} = E \\ K_{2} = 10435 \ J {/eq}