A 6 pound object stretches a spring 3 inches. How much work is required to stretch this spring...

Question:

A 6 pound object stretches a spring 3 inches. How much work is required to stretch this spring from 3 to 5 inches?

Work:

Work is the amount of energy it takes to displace an object. With respect to a spring, this displacement is the difference between its equilibrium length and its compressed or stretched length. Work is given by

{eq}W = \int F\ dx {/eq}

Recall also Hooke's Law, which relates force to the spring constant {eq}k {/eq}:

{eq}\begin{align*} F &= kx \end{align*} {/eq}

Answer and Explanation:

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First, recall that weight is a force (it's an objects mass times the gravitational acceleration of the Earth), so we are told that when {eq}F =...

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Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.


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