A 60kg skier starts from rest from the top of a 50m high slope. If the work done by friction is...

Question:

A {eq}60kg {/eq} skier starts from rest from the top of a {eq}50m {/eq} high slope. If the work done by friction is {eq}-6.0\times 103 J {/eq}, what is the speed of the skier on reaching the bottom of the slope?

Conservation of Energy:

In the presence of a non-conservative force, the amount of work done in going from {eq}P \rightarrow Q {/eq} is

{eq}K_P + U_P = K_Q + U_Q + W_{P \rightarrow Q} {/eq}

Some of the initial energy must be lost to heat as a the frictional force acts.

Answer and Explanation:

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At the top of the hill (say Point {eq}P {/eq}), where the skier is at rest, the energy is

{eq}E_P = mgH. {/eq}

At the bottom on the hill (Point...

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Linear Momentum, Impulse & Energy Conservation

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Chapter 49 / Lesson 1
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In this lesson, you'll learn about linear momentum, impulse, and energy conservation. These are all important components of collisions, which can be large, small, and everything in between!


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