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A 7 kg ball is thrown into the air from ground level with an initial velocity of 24 m/s....

Question:

A 7 kg ball is thrown into the air from ground level with an initial velocity of 24 m/s. Determine the ball's maximum height. Use conservation of energy.

Conservation of Energy

The law of conservation of energy states that any form of energy cannot be created or destroyed. It is converted to one form of energy to another. Here, we are investigating the energy of a ball thrown into the air.

Answer and Explanation:

Given:

{eq}m = 7 \text{kg}\\ v = 24 \text{m}/\text{s}\\ {/eq}

Using the conservation of energy, we can calculate the maximum height of the ball.

{eq}PE = KE\\ \Rightarrow mgh = \frac{1}{2}mv^2\\ \Rightarrow h = \frac{(0.5) v^2}{g} = \frac{(0.5) (24 \text{m}/\text{s})^2}{9.8 \text{m}/\text{s}^2} = \boxed{29.4 \text{m}} {/eq}


Learn more about this topic:

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What is Energy Conservation? - Definition, Process & Examples

from ICSE Environmental Science: Study Guide & Syllabus

Chapter 1 / Lesson 6
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