A battery has an emf of \varepsilon = 3V, an internal resistance r = 12 \Omega, and is connected...

Question:

A battery has an emf of {eq}\varepsilon = 3V {/eq}, an internal resistance {eq}r = 12 \Omega {/eq}, and is connected to a resistor of {eq}R =55 \Omega {/eq}.

a . Express the current {eq}I {/eq} through {eq}\varepsilon, r {/eq} and {eq}R {/eq}

b . Calculate the numerical value of {eq}I {/eq} in {eq}A {/eq} .

c . Express the terminal voltage {eq}\Delta {/eq} through {eq}I {/eq} and {eq}R {/eq} .

d . Calculate numerical value of {eq}\Delta {/eq} in {eq}V {/eq} .

Ohm's Law:

When we have a simple series circuit with a supply E and a series equivalent resistance R, we determine the current in the circuit as the ratio of the emf to the resistance i.e. {eq}E = \frac{E}{R} {/eq}. This relationship is called Ohm's Law. The equivalent series resistance is the resistance value that can replace all the resistors without changing the current supplied in the circuit.

Answer and Explanation:


Part a


By Ohm's Law, the current I is the ratio of voltage to the equivalent resistance of the series circuit, i.e.

{eq}I = \frac{V}{R} =...

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Series Circuit: Calculating Voltage Drops with Ohm's Law

from Physics 112: Physics II

Chapter 9 / Lesson 5
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