A cart rolls down a hill. If the cart weighs 8.7 kg and the cart starts at a height of 3.0 m,...

Question:

A cart rolls down a hill. If the cart weighs 8.7 kg and the cart starts at a height of 3.0 m, what is the final velocity of the cart?

Conservation Of Energy:

For the conservation of energy of the object the total energy stored inside the body remain conserved and can be converted from one form into another, for example, a body placed at a particular height from the ground will be having some potential energy stored inside it and that energy will be converted into the kinetic energy when the object is allowed to fall.

Answer and Explanation:

Given

Mass of the cart is {eq}m=8.7\ kg {/eq}

Height at which the cart is placed is {eq}h=3\ m {/eq}

From the conservation of energy:

{eq}P.E=K.E\\ mgh=\frac{1}{2}mv^2\\ v=\sqrt{2gh}\\ v=\sqrt{2\times 9.81\times 3}\\ v=58.86\ m/s {/eq}

Thus, the velocity of the cart at the bottom of the hill will be 58.86 m/s


Learn more about this topic:

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Energy Conservation and Energy Efficiency: Examples and Differences

from Geography 101: Human & Cultural Geography

Chapter 13 / Lesson 9
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