A certain rain cloud at an altitude of 2.01 km contains 3.20 x 10^7 kg of water vapor. How long...

Question:

A certain rain cloud at an altitude of {eq}2.01 \, \mathrm{km} {/eq} contains {eq}3.20 \times 10^7 \, \mathrm{kg} {/eq} of water vapor. How long would it take for a 2.27-kilowatt pump to raise the amount of water from the Earth's surface to the cloud's position?

Gravitational Potential Energy:

The Gravitational Potential Energy of an object with respect to Earth's surface is given by:

{eq}P.E. = m g h {/eq}

where

  • m = Mass of the object
  • g = Acceleration due to gravity
  • h = Height of the object from the Earth's surface

Answer and Explanation:

Here, we need to find the time taken by a 2.27 kW pump to raise the given amount of water from the Earth's surface to the cloud's position.

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Gravitational Potential Energy: Definition, Formula & Examples

from UExcel Physics: Study Guide & Test Prep

Chapter 5 / Lesson 6
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