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A circuit is in a uniform magnetic field, that is into the page, and is decreasing in magnitude,...

Question:

A circuit is in a uniform magnetic field, that is into the page, and is decreasing in magnitude, at the rate of 150 tesla/second. What current does the ammeter read?

Induced Current:


The ammeter is the device to measure current flowing in the electrical circuit. A galvanometer can be made into an ammeter by connecting a shunt resistance in parallel to it. The rate of change of magnetic flux produces induced current.

Answer and Explanation:


Lets us assume the following variables,

{eq}V \rightarrow \textrm{voltage across the terminals}\\ \epsilon \rightarrow \textrm{electromotive force}\\ \dfrac{d\phi}{dt} \rightarrow \textrm{rate of change of magnetic flux}\\ B \rightarrow \textrm{magnetic field} r \rightarrow \textrm{internal resistance in the circuit}\\ A \rightarrow \textrm{area of cross-section}\\ {/eq}


We know that the e.m.f (electromotive force) is the rate of change of magnetic flux which can be mathematically represented as,

{eq}\epsilon = \dfrac{d\phi}{dt} \Rightarrow \dfrac{d(A.B)}{dt}\\ \epsilon = A.\; \dfrac{d\phi}{dt}\Rightarrow (0.01\;\rm m^2)\dfrac{dB}{dt}\\ \epsilon = (0.01\;\rm m^2)(150\;\rm T/s)\\ \boxed{\epsilon \approx 1.5\;\rm V}......(1) {/eq}


The relation between the e.m.f and voltage (electric potential difference) is mathematically given as,

{eq}\epsilon = V + Ir\\ I = \dfrac{\epsilon - V}{r}\\ I = \dfrac{1.5\;\rm V - 1.0\;\rm V}{0.2\;\rm \Omega}\\ \boxed{I = 2.5\;\rm A} {/eq}


Following assumptions were made,

{eq}V = 1.0\;\rm V\\ r = 0.2\;\rm \Omega\\ A = 0.01\;\rm m^2 {/eq}


Learn more about this topic:

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Lenz's Law, Magnetic Flux and Motional EMF

from GACE Physics (530): Practice & Study Guide

Chapter 23 / Lesson 9
8.2K

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