A cyclotron is accelerating proton where the applied magnetic field is 2 T, the potential gap is...

Question:

A cyclotron is accelerating proton where the applied magnetic field is 2 T, the potential gap is 10{eq}KV {/eq} then how much turn the proton has to moving between these to acquire a kinetic energy 20{eq}meV {/eq} a) 200 b) 300 c) 150 d)100

The change in Kinetic Energy and Electric Potential Difference:

The change in kinetic energy of a charged particle when it passes through a potential difference {eq}\Delta V {/eq} is given by the equation;

{eq}\Delta (K.E.) = q \Delta V {/eq}

where, {eq}q {/eq} is the charge of the charge particle and {eq}\Delta (K.E.) {/eq} is the change in the kinetic energy.

Answer and Explanation:

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Given

  • The applied magnetic field is {eq}B = 2\ T {/eq}
  • The potential difference is {eq}\Delta V = 10\ KV {/eq}
  • The kinetic energy (K.E.) of the...

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Kinetic Energy: Examples & Definition

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Chapter 4 / Lesson 14
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