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A doubly charged ion is accelerated to an energy of 32.0 \ keV by the electric field between two...

Question:

A doubly charged ion is accelerated to an energy of {eq}32.0 \ keV {/eq} by the electric field between two parallel conducting plates separated by {eq}3.20 \ cm {/eq}. What is the electric field strength between the plates?

Electric Field:

In electrostatics, the term electric field can be defined as the ratio or the fraction of electric force acting on the per-unit charge. The measurable unit for the electric field in Newton per Coulomb.

Answer and Explanation:

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Given data:

  • The double charged ion energy is {eq}W = 32.0\,{\rm{keV}} = 32.0 \times {10^3}\,{\rm{eV}} {/eq}
  • The separated distance is {eq}d =...

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Electric Fields Practice Problems

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Chapter 17 / Lesson 8
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