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A fisherman's scale stretches 3.5 cm when a 2.1 kg fish hangs from it. I know that k=590 N/m and...

Question:

A fisherman's scale stretches 3.5 cm when a 2.1 kg fish hangs from it. I know that k=590 N/m and f=2.7 Hz.

How do I find the amplitude of vibration if the fish is pulled down 3.2 cm more and released so that it vibrates up and down?

Hooke's law

In equation form it is written as {eq}F = -kx{/eq}

wherein F is the force of the spring, k is the spring constant and x is the displacement of the spring from its equilibrium state. The greater the x and k, the greater the F

Answer and Explanation: 1

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Given:

  • Distance {eq}x = 3.5 \rm\ cm = 0.035 \rm\ m{/eq}
  • Mass {eq}m = 2.1 \rm\ kg{/eq}


The fish is pulled 3.2 centimeters, therefore it is the...

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Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.


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