# A fisherman's scale stretches 3.5 cm when a 2.1 kg fish hangs from it. I know that k=590 N/m and...

## Question:

A fisherman's scale stretches 3.5 cm when a 2.1 kg fish hangs from it. I know that k=590 N/m and f=2.7 Hz.

How do I find the amplitude of vibration if the fish is pulled down 3.2 cm more and released so that it vibrates up and down?

## Hooke's law

In equation form it is written as {eq}F = -kx{/eq}

wherein F is the force of the spring, k is the spring constant and x is the displacement of the spring from its equilibrium state. The greater the x and k, the greater the F

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Given:

• Distance {eq}x = 3.5 \rm\ cm = 0.035 \rm\ m{/eq}
• Mass {eq}m = 2.1 \rm\ kg{/eq}

The fish is pulled 3.2 centimeters, therefore it is the...

Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.