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A force of 10 lb is required to hold a spring stretched 8 in. beyond its natural length. How much...

Question:

A force of 10 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work is done in stretching it from its natural length to 11 in. beyond its natural length?

Applications of Hooke's Law:

To solve this problem, we will use Hooke's Law, which states: If a force {eq}F {/eq} is applied on a spring and its displacement is {eq}x {/eq} units, then we can write,

{eq}F = kx {/eq}. Here, {eq}k {/eq} is the spring constant.

Answer and Explanation: 1

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As 10 lbs is required to hold a spring 8 inches from its natural length, we can say that:

  • Force {eq}(F) = 10 {/eq} lbs
  • Displacement {eq}(x) = 8 \...

See full answer below.


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Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.


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