# A force of 1250 pounds compresses a spring 5 inches from its natural length. Find the work done...

## Question:

A force of 1250 pounds compresses a spring 5 inches from its natural length. Find the work done in compressing the spring 8 additional inches.

## Spring Constant:

For spring, the spring constant is an indication of its stiffness. In other words, we can define the spring constant as the total force needed to deform (either compress or stretch) the unit length of the spring. If some force is applied in the spring and the spring is distorted, we can calculate the spring constant using the following expression.

{eq}\text{Applied}\ \text{force}=\text{Spring}\ \text{constant}\times \text{Deformed}\ \text{length}\ \text{of}\ \text{spring} {/eq}

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Given data

• The total force is {eq}F=1250\ \text{pounds} {/eq}
• The compressed length of spring is {eq}{{l}_{1}}=5\ \text{inches}=\left( 5\... Hooke's Law & the Spring Constant: Definition & Equation

from

Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.