# A force of 2 N stretches an elastic rubber by 0.2 m. Find the elastic constant.

## Question:

A force of 2 N stretches an elastic rubber by 0.2 m. Find the elastic constant.

## Hook's Law:

Hook's law states that the restoring force applied by a spring or by an elastic body is directly proportional to the negative of the elongation. It can be expressed as such;

{eq}\color{red}{F_{k} = -kx } {/eq}

where;

• k is spring constant or elastic constant.
• x is the elongation in the spring after stretching it from its equilibrium position.

Note: Spring constant depends on the material used to make it.

## Answer and Explanation: 1

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Given:

• Force applied on an elastic rubber is {eq}F = 2.0 \, N {/eq}
• Elongation of an elastic rubber after stretching is {eq}x = 0.2 \, m {/eq}

Acc...

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#### Learn more about this topic: Hooke's Law & the Spring Constant: Definition & Equation

from

Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.