A force of 2 N stretches an elastic rubber by 0.2 m. Find the elastic constant.

Question:

A force of 2 N stretches an elastic rubber by 0.2 m. Find the elastic constant.

Hook's Law:

Hook's law states that the restoring force applied by a spring or by an elastic body is directly proportional to the negative of the elongation. It can be expressed as such;

{eq}\color{red}{F_{k} = -kx } {/eq}

where;

  • k is spring constant or elastic constant.
  • x is the elongation in the spring after stretching it from its equilibrium position.

Note: Spring constant depends on the material used to make it.

Answer and Explanation: 1

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Given:

  • Force applied on an elastic rubber is {eq}F = 2.0 \, N {/eq}
  • Elongation of an elastic rubber after stretching is {eq}x = 0.2 \, m {/eq}

Acc...

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Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.


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