A force of 5.0 N is required to stretch a certain spring by 1.5 cm . (a) How far must this...


A force of {eq}5.0 \ N {/eq} is required to stretch a certain spring by {eq}1.5 \ cm {/eq}.

(a) How far must this spring be stretched for its potential energy to be {eq}0.025 \ J {/eq}?

(b) How much stretch is required for the spring potential energy to be {eq}0.080 \ J {/eq}?

Hooke's Law:

According to Hooke's law, the stretch or elongation of the spring due to the impressed force is directly proportional to the magnitude of the impressed force. Mathematically,

{eq}F=Kx {/eq}


  • {eq}K {/eq} is the spring constant
  • {eq}x {/eq} is the displacement from the mean position

Answer and Explanation: 1

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Given data:

  • Force exerted on the spring {eq}F=5 \ N {/eq}
  • Stretch in the spring due to 5 N force {eq}x=1.5 \ cm=0.015 \ m {/eq}
  • {eq}K {/eq} be...

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Learn more about this topic:

Hooke's Law & the Spring Constant: Definition & Equation


Chapter 4 / Lesson 19

After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.

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