A force of 5N extend a spring of natural length 0.5 m by 0.01 m. what will the length of the...

Question:

A force of 5N extend a spring of natural length 0.5 m by 0.01 m. what will the length of the spring be when a force 20N is applied?

Hooke's Law:

A spring of force constant (k) is fixed under the base of a platform. The base is pushed by exerting a force (F) so that the compression in the spring is (x). In this example, the spring imposes a force of the same magnitude in the opposite direction. Here, the force (F) is directly proportional to the compression caused in the spring.

Answer and Explanation:

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Given data:

  • Force in the first case, {eq}F_{1} = 5 \ \rm N {/eq}
  • Force in the second case, {eq}F_{2} = 20 \ \rm N {/eq}
  • Natural length of spring,...

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Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.


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