A hard ball dropped from a height of 1 m in the earth's gravitational field bounces to a height...

Question:

A hard ball dropped from a height of 1 m in the earth's gravitational field bounces to a height of 95 cm. What will be the total distance traversed by the ball?

Distance:

The term "distance" is the measurement of the path that a particle or system particles covers during its motion. The distance does not depend upon the direction, therefore it is considered as a scalar quantity.

Here, the ball moves only along the verticle direction. The total distance traveled by the ball is equal to the total length of the path.

Therefore, total distance traveled by the ball,

{eq}\begin{align*} d &= (1 \ m) + (0.95 \ m)\\ d &= 1.95 \ m. \end{align*}. {/eq}