# A horizontal spring is attached to a block with a mass of 8kg. The block is pulled out to a...

## Question:

A horizontal spring is attached to a block with a mass of 8kg. The block is pulled out to a distance of 15cm with an external force of 200 N. If the mass is released (i.e. no more external force) from this point, what will be its acceleration when it is 10cm from equilibrium?

## Spring-Mass System:

When we snugly pull the mass attached to the spring and release it, we can notice that, initially, the mass accelerates rapidly, and then its acceleration ceases. This happens because the acceleration imparted to the mass bound to the spring is proportional to the restoring force provided by the spring. Mathematically:

$$\rm Restoring \ force=mass \times acceleration$$

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Given data:

• {eq}m=\rm 8 \ kg {/eq} is the mass of the block
• {eq}x=\rm 15 \ cm=0.15 \ m {/eq} is the deformation of the spring
• {eq}F=\rm 200 \... Hooke's Law & the Spring Constant: Definition & Equation

from

Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.