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A K+ ion and a Cl- ion are directly across from each other on opposite sides of a membrane 7.9 nm...

Question:

A {eq}K+ {/eq} ion and a {eq}Cl- {/eq} ion are directly across from each other on opposite sides of a membrane 7.9 nm thick. What is the the electric force on the {eq}K+ {/eq} ion due to the {eq}Cl- {/eq} ion? Ignore the presence of other charges.

Electric Force of Interaction Between Two Charges:


According to Coulomb's law, the electric force of interaction on one static point charge {eq}q_1 {/eq} due to other charge {eq}q_2 {/eq}, placed at a distance {eq}r {/eq} is given by

{eq}F = k\cdot \dfrac{q_1q_2}{r^2}\\ {/eq}

  • {eq}k {/eq} = Coulomb's constant.

The direction of this force is along the line joining the two charges.

This electric force between the two charges is repulsive in nature if the polarity of the charges are same and attractive if the polarities of the charges are different.

Answer and Explanation:

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Constants used:

  • {eq}k = 9\times 10^9\ Nm^2/ C^2 {/eq}.
  • {eq}e {/eq} = elementary charge = {eq}1.6\times 10^{-19}\ C {/eq}.


Assumptions and...

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Coulomb's Law: Variables Affecting the Force Between Two Charged Particles

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Chapter 6 / Lesson 3
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In the 18th century, Charles Coulomb uncovered the secrets of electrostatic force between charged particles. The results of his experiments led to what is now known as Coulomb's Law, which tells us how force, charge, and distance are all related.


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