# A marble column of cross-sectional area 1.1 m^2 supports a mass of 35 000 kg. The elastic modulus...

## Question:

A marble column of cross-sectional area {eq}1.1 \, \mathrm{m^2} {/eq} supports a mass of {eq}35\,000 \, \mathrm{kg} {/eq}. The elastic modulus for marble is {eq}5.0 \times 10^{10} \, \mathrm{N/m^2} {/eq}.

(1) What is the stress within the column?

(2) What is the strain on the column?

## Hooke's Law

Hooke's Law states that within the elastic limit, the stress developed in a body is directly proportional to the strain in the body. Mathematically

{eq}\begin{align} E = \frac{Stress}{Strain} \end{align} {/eq}

Become a Study.com member to unlock this answer! Create your account

• Area of cross section {eq}A = 1.1 m^2 {/eq}
• mass {eq}m = 35000 kg {/eq}
• Modulus of elasticity {eq}E = 5.0 \times 10^{10} N/m^2 {/eq}

Part (1)Stress...

Hooke's Law & the Spring Constant: Definition & Equation

from

Chapter 4 / Lesson 19
202K

After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.