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A mass of 2.62 kg stretches a vertical spring of 0.320 m. If the spring is stretched an...

Question:

A mass of 2.62 kg stretches a vertical spring of 0.320 m. If the spring is stretched an additional 0.130 m and released, how long does it take to reach the (new) equilibrium position again?

Spring-mass System:

Like the period of oscillation of the pendulum does not depend upon the length of the arc traveled by the bob (for a small-angle), the period of the spring-mass system does not depend upon the amount of extension or compression of the spring from the mean position. The period of the spring-mass system changes with changing the mass attached to the spring, that's why it used under microgravity to calculate the mass of an astronaut.

Answer and Explanation:

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Given data:

  • {eq}m=\rm 2.62 \ kg {/eq} is the mass
  • {eq}x=\rm 0.320 \ m {/eq} is the extension of the spring
  • {eq}k {/eq} is the spring constant
  • {e...

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Practice Applying Spring Constant Formulas

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Chapter 17 / Lesson 11
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In this lesson, you'll have the chance to practice using the spring constant formula. The lesson includes four problems of medium difficulty involving a variety of real-life applications.


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