A massless spring with spring constant 16.7 N/m hangs vertically. A body of mass 0.220 kg is...

Question:

A massless spring with spring constant 16.7 N/m hangs vertically. A body of mass 0.220 kg is attached to its free end and then released. Assume that the spring was unstretched before the body was released. How far below the initial position does the body descend?

The Hooke's law Force:

A spring, when stretched or compressed, will try to resist the deformation. A restoring force will act to restore the spring to its initial configuration. The restoring force has the Hooke's Law form and is proportional to the displacement of the spring and is directed opposite to the displacement.

Answer and Explanation: 1

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Given that a massless spring with spring constant {eq}\displaystyle {k=16.7 \ N/m } {/eq} hangs vertically. Given that a body of mass...

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Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.


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