# A mix for 15 servings of instant potatoes requires one and seven eighths cups of water. Use this...

## Question:

A mix for 15 servings of instant potatoes requires one and seven eighths cups of water. Use this information to decide how much water is needed if you want to make 5 servings.

## Proportions and Variation:

In any numerical ratio, this denotes a relationship between two numbers {eq}x {/eq} and {eq}y {/eq}. On the other hand, a proportion shows the similarity between two ratios. When two variables are dependent, variations in the magnitude of one variable will have a proportional effect on the other. When there is an increase or decrease of a variable {eq}x {/eq} with respect to another {eq}y {/eq}, for a ratio or constant K, variations are present. In the case that we have a direct variation, it happens that when one variable increases the other increases, which can also be written as: {eq}\frac{{{y_1}}}{{{x_1}}} = \frac{{{y_2}}}{{{x_2}}} {/eq}.

{eq}\eqalign{ & {\text{In this specific case }}{\text{,we have two proportional values }}\,x\,\left( {servings{\text{ }}of{\text{ }}instant{\text{ }}potatoes} \right){\text{ }} \cr & {\text{and }}y\,\left( {cups{\text{ }}of{\text{ }}water} \right){\text{ that have a variation in directly proportional form}}{\text{. }} \cr & {\text{So we have:}} \cr & \,\,\,\,{x_1} = 15\,servings{\text{ }}of{\text{ }}instant{\text{ }}potatoes \cr & \,\,\,\,{y_1} = 1\frac{7}{8} = 1.875\,cups{\text{ }}of{\text{ }}water \cr & \,\,\,\,{x_2} = 5\,servings{\text{ }}of{\text{ }}instant{\text{ }}potatoes \cr & \,\,\,\,{y_2} = ?\,\,cups{\text{ }}of{\text{ }}water \cr & {\text{Since}}{\text{, }}x{\text{ and }}y{\text{ vary directly}}{\text{, then}}{\text{, when }}x{\text{ decreases it also }} \cr & {\text{decreases }}y{\text{. For this reason}}{\text{, it must be satisfied that:}} \cr & \,\,\,\,\frac{{{y_2}}}{{{x_2}}} = \frac{{{y_1}}}{{{x_1}}} \cr & {\text{So if we do cross - multiplying:}} \cr & \,\,\,\,{y_2} \cdot {x_1} = {y_1} \cdot {x_2} \cr & {\text{Now}}{\text{, solving for }}\,{y_2}{\text{:}} \cr & \,\,\,\,{y_2} = \frac{{{y_1} \cdot {x_2}}}{{{x_1}}} \cr & {\text{So}}{\text{, substituting the given values:}} \cr & \,\,\,\,{y_2} = \frac{{1.875 \times 5}}{{15}} = 0.625\,cups{\text{ }}of{\text{ }}water \cr & {\text{Therefore}}{\text{, you will need }}\boxed{0.625\,cups{\text{ }}of{\text{ }}water}{\text{ to make 5 }}servings \cr} {/eq} 