# A Modified Atwood's machine (the pulley with two mass system used in class on in the Modified...

## Question:

A Modified Atwood's machine (the pulley with two mass system used in class on in the Modified Atwood phyletic) has a 10.0 N cart on a frictionless, horizontal track with a 10.0 N hanging weight attached to a string connecting the two weights. A second track is set up where the hanging weight is replaced by a person who can maintain a 10.0 N pull on the string (as measured with a force probe). Which set-up has the greater acceleration?

## Application of Newton's Second Law

Newton's second law relates the force applied *F* on an object of mass *m* to the acceleration *a* produced on it. So force exerted on the object {eq}F = m a
{/eq}. Since acceleration is the rate of change of velocity the force can be expressed as the rate of change of momentum of the object. Then force {eq}F = \dfrac { d ( m v ) } { dt } = \dfrac { d P } { dt }
{/eq}.

- For the application of second law we need to consider the net force acting on the object. There will be number of forces acting on the object under consideration like frictional forces etc. In that case one has to get the resultant force acting on the object.
- Both force and acceleration are vectors and both will be acting in the same direction.
- If we consider a system, the second law of Newton has to be applied individually for all the constituent objects in the system considering all individual forces acting on it.

## Answer and Explanation: 1

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View this answer**Given data**

- Weight of the cart free to move on the friction-less cart in the horizontal track {eq}W = 10.0 \ N {/eq}

- In one case a second cart of...

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Chapter 17 / Lesson 5In this lesson, we will introduce force and acceleration formulas using Newton's Force Laws and demonstrate kinematic equations, including examples, to solve real-world problems.