A particle with a mass of 2.0 x 10^{-5} kg and a charge of +2.0 micro C is released in a...


A particle with a mass of {eq}\rm 2.0 \times 10^{-5} \ kg {/eq} and a charge of {eq}\rm +2.0 \ \mu C {/eq} is released in a (parallel plate) uniform horizontal electric field of 12 N/C.

(a) How far horizontally does the particle travel in 0.50 s?

(b) What is the horizontal component of its velocity at that point?

(c) If the plates are 5.0 cm on each side, how much charge is on each?

Electric Field:

The electric field is related to the electric force on a point charge. Thus, in a uniform electric field, a particle with a charge will experience a constant force F given by;

{eq}F = qE {/eq}

Here, q is the charge of the particle, E is the electric filed.

Answer and Explanation:

Let m = {eq}2.0 \times 10^{-5} \ \textrm{kg} {/eq} be the mass of the particle, q = {eq}2.0 \times 10^{-6} \ \textrm C {/eq} be the charge of the...

See full answer below.

Become a member to unlock this answer! Create your account

View this answer

Learn more about this topic:

Electric Fields Practice Problems

from Physics 101: Intro to Physics

Chapter 17 / Lesson 8

Related to this Question

Explore our homework questions and answer library