# A person walks 28.8 degrees north of east for 2.06 km. Another person walks due north, then due...

## Question:

A person walks 28.8 degrees north of east for 2.06 km. Another person walks due north, then due east to arrive at the same location. How far due north would this person walk? Answer in units of km.

## Vector components:

{eq}V_x = V \cos{\theta} \\ V_y = V \sin{\theta} {/eq}

Where {eq}V {/eq} is the vector,

{eq}V_x {/eq} is the x-component of the vector,

{eq}V_y {/eq} is the y-component of the vector, and

{eq}\theta {/eq} is the angle of the vector.

If we set as the east as x component and the north as the y component of the resultant displacement, we can solve for the displacement in north by trigonometric identities

{eq}V_y = V \sin{\theta} \\ V_y = 2.06 \sin{28.8} \\ V_y = 0.99 Km {/eq}