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A proton with an initial speed of 800,000 m/s is brought to rest by an electric field. a. What...

Question:

A proton with an initial speed of 800,000 m/s is brought to rest by an electric field.

a. What was the potential difference that stopped the proton?

b. What was the initial kinetic energy of the proton, in electron volts?

Kinetic Energy of the Proton

The change in kinetic energy of the charged particle is proportional to the potential difference.

{eq}\Delta K = 0 - \dfrac 12 mv^2 \\ \ = \ - q \Delta V {/eq}

The mass of the proton

{eq}m_p = 1.67 \times 10^{-27} kg \\ the \ charge \ of \ the \ proton\\ q = + 1.6 \times 10^{-19} \ C {/eq}

Answer and Explanation:

Given:

{eq}m_p = 1.67 \times 10^{-27} kg \\ the \ charged \ of \ the \ proton\\ q = + 1.6 \times 10^{-19} \ C \\ v = 800,000 \ \dfrac ms {/eq}

a...

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Protons: Definition, Charge & Mass

from General Studies Science: Help & Review

Chapter 28 / Lesson 2
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