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A spring hangs at rest from a lab stand in physics class. When a mass of 2.1kg is attached to the...

Question:

A spring hangs at rest from a lab stand in physics class. When a mass of 2.1kg is attached to the spring, it stretches downward 14cm to a new equilibrium position (not oscillating). What is the stiffness constant for the spring?

Hooke's Law:

The force that extends or compresses a spring is described by Hooke's Law, where the force is proportional to the displacement in the spring caused by the force applied. The spring constant that relates the two quantities is denoted by the symbol {eq}k{/eq}.

Answer and Explanation:

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Given Information

  • The mass is {eq}m = 2.1\;{\rm{kg}} {/eq}
  • The displacement of the spring is {eq}x = 14\;{\rm{cm}} =...

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Practice Applying Spring Constant Formulas

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Chapter 17 / Lesson 11
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In this lesson, you'll have the chance to practice using the spring constant formula. The lesson includes four problems of medium difficulty involving a variety of real-life applications.


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