A spring has natural length 26 cm. Compare the work W_1 done in stretching the spring from 26 cm...

Question:

A spring has natural length 26 cm. Compare the work {eq}W_1 {/eq} done in stretching the spring from 26 cm to 36 cm with the work {eq}W_2 {/eq} done in stretching it from 36 cm to 46 cm. (Use K for the spring constant)

How are {eq}W_2 {/eq} and {eq}W_1 {/eq} related?

Hooke's Law:

According Hooke's law, every elastic body is proportional to the deformation produced, the deforming force will have to have the same value and direction, but its meaning will be the opposite. Using Hooke's law which tells you that the force required to stretch a spring a distance of x meters from its natural length is {eq}F(x)=kx,k>0. {/eq}

Answer and Explanation: 1

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You know that spring's natural length is 26 cm so, x=0 . For first case when spring is 36 cm, spring is stretched (36-26)=10cm or 0.1m and in second...

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Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.


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