A spring is displaced 25 cm from equilibrium with a 15 kg mass hanging vertically from it. If you...

Question:

A spring is displaced 25 cm from equilibrium with a 15 kg mass hanging vertically from it. If you add another 12 kg to the 15 kg that is hanging, what is the spring's displacement from equilibrium?

Hooke's Law:

When the spring hangs freely with no external mass attached to its free end, the position of the free end is called the equilibrium position. If we snugly add mass to the free end, the spring stretches, and the distance through which the free end displaced from the equilibrium position is called deformation of the spring. Mathematically:

$$\rm Applied \ force=force \ constant \times deformation \ of \ spring $$

Answer and Explanation:

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Given data:

  • {eq}m_1=\rm 15 \ kg {/eq} is the mass attached to the spring
  • {eq}x_1=\rm 25 \ cm {/eq} is the initial deformation of the spring
  • {eq}m...

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Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.


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