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A spring oriented vertically is attached to a hard horizontal surface as in the figure below. The...

Question:

A spring oriented vertically is attached to a hard horizontal surface as in the figure below. The spring has a force constant of 1.46 kN/m. How much is the spring compressed when a object of mass m = 2.30 kg is placed on top of the spring and the system is at rest?

Hooke's Law:

Let us assume a flexible plastic having force constant (k) is compressed by a distance (x) by applying an external force of magnitude (F). In this example, the flexible plastic rod will impose a force of similar magnitude in the reverse direction. In this case, the force (F) will be directly proportional to compression (x) caused in the plastic rod.

Answer and Explanation: 1

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Given data:

  • Mass of the object, {eq}m = 2.30 \ kg {/eq}
  • Spring constant, {eq}k = 1.46 \ k N/m {/eq}

Let the compression in the spring be x.

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Hooke's Law & the Spring Constant: Definition & Equation

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Chapter 4 / Lesson 19
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After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.


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