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A spring stretches 0.150 m when a 0.300 kg mass is gently attached to it. The spring is then set...

Question:

A spring stretches 0.150 m when a 0.300 kg mass is gently attached to it. The spring is then set up horizontally with the 0.300 kg mass resting on a frictionless table. The mass is pushed so that the spring is compressed 0.300 m from the equilibrium point, and released from rest. What is the maximum velocity of the block?

Energy Stored by a Spring:

When a spring of constant k is acted upon by a force such that it got compressed or stretched by a distance x it tries to bring the system to equilibrium.

Then the potential energy stored by the spring is given by {eq}E_P= \frac{1}{2}kx^2 {/eq}

Answer and Explanation: 1

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Given:

A spring stretches x = 0.150 m when a m = 0.300 kg mass is gently attached to it.

Let the spring constant be k.

The spring stretches due to...

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Practice Applying Spring Constant Formulas

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Chapter 17 / Lesson 11
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In this lesson, you'll have the chance to practice using the spring constant formula. The lesson includes four problems of medium difficulty involving a variety of real-life applications.


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