# A spring stretches by 10 cm when a 2 kg mass is hung from it. What mass would stretch it by 15 cm?

## Question:

A spring stretches by {eq}10 \ \rm cm {/eq} when a {eq}2 \ \rm kg {/eq} mass is hung from it. What mass would stretch it by {eq}15 \ \rm cm {/eq}?

## The Spring Force:

If we attach an object to the end of a spring and then stretch or compress the spring, then the object will quickly move back to its original position. This is because the spring exerts a force on the object when it is stretched or compressed. This is called the restoring force, and its magnitude is given by Hooke's law:

{eq}F = kx {/eq}

Here, {eq}x {/eq} is the spring's current displacement from its natural length, or equilibrium position, and {eq}k {/eq} is the spring constant (measured in {eq}\frac{N}{m} {/eq}), which tells us how tight the spring is and thus how difficult it is to stretch it.

## Answer and Explanation: 1

Become a Study.com member to unlock this answer! Create your account

When the first mass is hung from the spring, it will stretch the spring until the mass comes to a stop. At this point, the forces acting on the mass...

See full answer below.

#### Learn more about this topic:

Hooke's Law & the Spring Constant: Definition & Equation

from

Chapter 4 / Lesson 19
202K

After watching this video, you will be able to explain what Hooke's Law is and use the equation for Hooke's Law to solve problems. A short quiz will follow.